6c^2+6c-336=0

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Solution for 6c^2+6c-336=0 equation:



6c^2+6c-336=0
a = 6; b = 6; c = -336;
Δ = b2-4ac
Δ = 62-4·6·(-336)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-90}{2*6}=\frac{-96}{12} =-8 $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+90}{2*6}=\frac{84}{12} =7 $

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